FRIHOST FORUMS SEARCH FAQ TOS BLOGS COMPETITIONS
You are invited to Log in or Register a free Frihost Account!

primes function in python




import numpy

def primesfrom2to(n):
""" Input n>=6, Returns a array of primes, 2 <= p < n """
sieve = numpy.ones(n/3 + (n%6==2), dtype=numpy.bool)
for i in xrange(1,int(n**0.5)/3+1):
if sieve[i]:
k=3*i+1|1
sieve[ k*k/3 ::2*k] = False
sieve[k*(k-2*(i&1)+4)/3::2*k] = False
return numpy.r_[2,3,((3*numpy.nonzero(sieve)[0][1:]+1)|1)]

def primes1(n):
""" Returns a list of primes < n """
sieve = [True] * (n/2)
for i in xrange(3,int(n**0.5)+1,2):
if sieve[i/2]:
sieve[i*i/2::i] = [False] * ((n-i*i-1)/(2*i)+1)
return [2] + [2*i+1 for i in xrange(1,n/2) if sieve[i]]

def primes2(n):
""" Input n>=6, Returns a list of primes, 2 <= p < n """
n, correction = n-n%6+6, 2-(n%6>1)
sieve = [True] * (n/3)
for i in xrange(1,int(n**0.5)/3+1):
if sieve[i]:
k=3*i+1|1
sieve[ k*k/3 ::2*k] = [False] * ((n/6-k*k/6-1)/k+1)
sieve[k*(k-2*(i&1)+4)/3::2*k] = [False] * ((n/6-k*(k-2*(i&1)+4)/6-1)/k+1)
return [2,3] + [3*i+1|1 for i in xrange(1,n/3-correction) if sieve[i]]



0 blog comments below




FRIHOST HOME | FAQ | TOS | ABOUT US | CONTACT US | SITE MAP
© 2005-2011 Frihost, forums powered by phpBB.