[Help]Reading images from folder (permissions)

Quote from my other post (not in correct section)

Quote:

[ENG]
I'm making (or trying) my own image gallery in PHP and MySQL, the script works fine, i can upload images perfectly and these are saved on a especific folder.
I'm working under a subdomain (sub.domain.frihost.net). My files are in "public_html/subdomain" and images are in "public_html/subdomain/images", but when i try to see those images Error 403 appear.
The folder permission is 777 like old file in there, but new uploaded files dont. I must set permission to 777 manually every file uploaded to see it.
My question: does exist any folder with public acces for this ??? I mean, i dont want to set 777 every file uploaded

Thanks a lot !!!!!!!!!!!!!!!!!

So, anyone can help me or give me a tip to solve this problem ??? Maybe a PHP code ???
this is my upload PHP script:

Code:

<?php

$server="localhost"; /* Nuestro server mysql: */
$database="xxxxxxxx"; /* Nuestra base de datos */
$dbpass="xxxxxxxxx"; /*Nuestro password */
$dbuser="xxxxxxx"; /* Nuestro user */

//datos del arhivo
$nombre_archivo = $HTTP_POST_FILES["userfile"]["name"];
$tipo_archivo = $HTTP_POST_FILES["userfile"]["type"];
$tamano_archivo = $HTTP_POST_FILES["userfile"]["size"];

//compruebo si las características del archivo son las que deseo
if (!((strpos($tipo_archivo, "gif") || strpos($tipo_archivo, "jpeg")) && ( $tamano_archivo < 1000000)))
{
echo "La extensión o el tamaño de los archivos no es correcta. <br><br><table><tr><td><li>Se permiten archivos .gif o .jpg<br><li>se permiten archivos de 100 Kb máximo.</td></tr></table>";
?>
<script language="javascript" type="HTML 4.0">
setTimeout("url()",3000);
function url()
{
window.history.back();
}
</script>
<?php
}
else
{
$nom_img= $nombre_archivo;

$directorio = 'fotos/';

if (move_uploaded_file($HTTP_POST_FILES['userfile']['tmp_name'],$directorio . "/" . $nom_img))
{
$diaactual= date("d");
$mesactual= date("m");
$anoactual= date("Y");
$fecha= $diaactual . "/" . $mesactual . "/" . $anoactual;

//NOS CONECTAMOS A LA BASE DE DATOS

$link=mysql_connect($server,$dbuser,$dbpass);

$query="INSERT INTO fotosup (titulo,comentario,ruta,autor,fecha) VALUES ('$titulo','$comentario','$nom_img','$autor','$fecha')";

$result=mysql_db_query($database,$query,$link);

if(mysql_affected_rows($link))
{
echo "Noticia ingresada correctamente";

} else
{
echo "Error introduciendo la Noticia";
} /* Cierre del else */

}
else
{
echo "error al subir la foto";
}
}

?>

Thanks !

lucianobosco

Problem solved !!!
Thanks anyway !!!

mahirharoon

use

Code:

<? chmod(0777) ?>

dac_nip

i think i'll try to do that myself Very Happy