Solve and get 50 Frih$
Round to the nearest tenth!
Trigonometry Problem - 50 Frih$
Solve and get 50 Frih$
Round to the nearest tenth!
sin 115 / x = sin 40 / 3
x = 4.23
By tenth is that 1/10.
if you I have rounded wrong x = 4.229893856
x = 4.23
By tenth is that 1/10.
if you I have rounded wrong x = 4.229893856
Corrrrect!
x = 4.2
^what I meant by tenth
x = 4.2
^what I meant by tenth
oh.. I rounded wrong because I thought wrong but the important thing is that the answer was correct.
Thanks for the 50 Frih$!
Thanks for the 50 Frih$!
| Peterssidan wrote: |
| sin 115 / x = sin 40 / 3
x = 4.23 By tenth is that 1/10. if you I have rounded wrong x = 4.229893856 |
well i am a littlebit confuse here (i am not good at trignometry), can you please tell me how is this solution?
I personally feel the answer should be 4.7
Me too..
Well, it might be stupid, but can't you use Cosinus and Sinus etc only in triangles with 1 ninety degree corner..? that's wa we learnt I think..
(srry for my bad english
)
Well, it might be stupid, but can't you use Cosinus and Sinus etc only in triangles with 1 ninety degree corner..?
that's wa we learnt I think..
(srry for my bad english
)It's the Law of sines.
very simple dude. Its the LAW of SINES.. hayy. it was already answered..
Yes it was the Law of Sines, this particular triangle is AngleSideSide.
You initially had to draw 2 different triangles, there could have been 2 different answers, but the second triangle equalled more than 180.
Edit, to answer your question:
You cannot use Law of Cosines because these are not right triangles, they are Oblique triangles.
You initially had to draw 2 different triangles, there could have been 2 different answers, but the second triangle equalled more than 180.
Edit, to answer your question:
| Gushe wrote: |
| Me too..
Well, it might be stupid, but can't you use Cosinus and Sinus etc only in triangles with 1 ninety degree corner..? that's wa we learnt I think..
(srry for my bad english ) |
You cannot use Law of Cosines because these are not right triangles, they are Oblique triangles.
Well.. I'm only 14 years old And I'm in fourth grade (It's appareantly different than in US etc..) and we didn't learn it yet.. though I could have tried
~Gushe
And I'm in fourth grade (It's appareantly different than in US etc..) and we didn't learn it yet.. though I could have tried
~Gushe
you could've solved it one sec i'll show how.
sin115=BD/3
BD=sin115*3
sin40=BD/x
x=BD/sin40=3,8
eeeh maybe not
edit:
lol my calculator still did radials
sin115=BD/3
BD=sin115*3
sin40=BD/x
x=BD/sin40=4,2
sin115=BD/3
BD=sin115*3
sin40=BD/x
x=BD/sin40=3,8
eeeh maybe not
edit:
lol my calculator still did radials
sin115=BD/3
BD=sin115*3
sin40=BD/x
x=BD/sin40=4,2
Quite easy.
May I suggest a new one?
Find the angle X
Winner gets 50 frih$
PS: I love Trigonometry!
May I suggest a new one?
Find the angle X
Winner gets 50 frih$
PS: I love Trigonometry!
If sen is the same as sinus
1 - (cos x)^2 - cos x - 1 = 0
(cos x)^2 + cos x = 0
x = pi
or if you want it in degrees: x = 180
1 - (cos x)^2 - cos x - 1 = 0
(cos x)^2 + cos x = 0
x = pi
or if you want it in degrees: x = 180
Great
Yes, sen is sinus.
frih$ 50 donated to Peterssidan.
Someone else, please, start another.
Edit: In fact, the correct answer is the following (with n, which is a natural number)
180 +/- n x 360 (example, 1260º is still correct, 1260 = 180 + (3 x 360) )
60 +/- n x 360
Sorry for my bad english, I supose you understood me.
Yes, sen is sinus.
frih$ 50 donated to Peterssidan.
Someone else, please, start another.
Edit: In fact, the correct answer is the following (with n, which is a natural number)
180 +/- n x 360 (example, 1260º is still correct, 1260 = 180 + (3 x 360) )
60 +/- n x 360
Sorry for my bad english, I supose you understood me.
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