ivan_07

a ball is thrown at an initial velocity of 30m/s at an angle θ with the horizontal. it hits point B, 30 m. below the point of origin in exactly 4 sec.

compute the value of θ

x=V(cosθ)t

x=30cosθ(4)

x=120cosθ

y=x(tanθ) - gx^2/2v^2cos^2θ

-30=120(Cosθsinθ)/cosθ - 9.81(120cosθ)^2/2(30)^2cos^2θ

9.81(120)^2/2(30)^2 -30 =120 sinθ

48.48=120 sinθ

θ=23.80

am i right with my answer???

compute the value of θ

x=V(cosθ)t

x=30cosθ(4)

x=120cosθ

y=x(tanθ) - gx^2/2v^2cos^2θ

-30=120(Cosθsinθ)/cosθ - 9.81(120cosθ)^2/2(30)^2cos^2θ

9.81(120)^2/2(30)^2 -30 =120 sinθ

48.48=120 sinθ

θ=23.80

am i right with my answer???