saratdear

Well, kind of.

It came to me somehow, and although it isn't anything path breaking, anything somebody couldn't discover themselves, and which I am not sure somebody has already discovered, I present it here:

The theorem, which shall be known henceforth as Sarat's theorem of square roots ( Copyrighted to me, of course)

The square root of a number is the product of its cube root and the square root of the cube root.

Mathematically, x^1/2 = [x^1/3*(x^1/3)^1/2]

It's easy to prove:

Take the RHS : x^1/3*x^1/6 = x^(1/3+1/6) = x^1/2

Eg : Square root of 64 ( 8 ) = Cube root of 64(4)*Square root of 4(2)

So...comments or suggestions?

Sarat

It came to me somehow, and although it isn't anything path breaking, anything somebody couldn't discover themselves, and which I am not sure somebody has already discovered, I present it here:

The theorem, which shall be known henceforth as Sarat's theorem of square roots ( Copyrighted to me, of course)

The square root of a number is the product of its cube root and the square root of the cube root.

Mathematically, x^1/2 = [x^1/3*(x^1/3)^1/2]

It's easy to prove:

Take the RHS : x^1/3*x^1/6 = x^(1/3+1/6) = x^1/2

Eg : Square root of 64 ( 8 ) = Cube root of 64(4)*Square root of 4(2)

So...comments or suggestions?

Sarat